1mereko sirf 15th ka ans chahiye...
baki ho gaya...
In a triangle ABC, coordinates of A are (1, 2) and the equations to medians through B and C are x + y = 5 and x = 4 respectively. Then,
14. The coordinates of the vertex C are
(A) (5, 3)
(B) (3, 4)
(C) (4, 3)
(D) (3, 5)
15. Length of the perpendicular drawn from the centroid to the side BC is
(A) √(17/18)
(B) √(18/17)
(C) 2√(17/18)
(D) 2√(18/17)
16. Area of the triangle ABC is (A) 7 (B) 8 (C) 9 (D) 10
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UP 0 DOWN 0 0 11
11 Answers
21@sky : considering u got coordi of C
centroid = (4,1) = ([x1 + x2 + x3]/3 , [y1 + y2 + y3]/3);
now u hav x2,x3 & y2,y3.........
and also hav x1 = 5-y1;
so u hav coordi of both B and C, u also hav thos of centroid;
ab to jus use formula 4 dis of a pt frm line, fir ho gaya
11yeah eureka that is what im getting
and that is option (b) sky is the ans right
24oh yeah.............[3][3][3]
diff presentation of answers makes it difficult.........
IMP FOR JEE::: Students always commit this blunder.......always try to reduce the options into simpler ones........
1this one is pretty easy..
i got C and area as well..
i think i made some mistake in getting the eqn of BC [12]