Ellipse Again

Since 0<a<pi/4,

The equation of the largest possible ellipse should be :

x²/2 + y²/1 = 1

Where focii wil be less than (-√2,√2)

In option C, it is given -1,1 so the rest of the real numbers are not included.

Since OM = OS1, it is lesser than length of minor axis. (2 x 1), hence M lies inside ellipse.

If focii are in interval (-√2,√2) then latus rectum interval should also have a negative limit. Since the interval given is (0,1/√2) hence option D is also wrong.

Hence correct answer is A

Ans given is A C D

Well i had told ya its A nd C..... u made me disprove myself !!!! had to sit fr hours fr this!!! [5]