The equation of ellipse is (x-1)^2+(y-2)^2=\frac{1}{9}(\frac{3x+4y-5}{5})^2
Then find the length of minor axis of ellipse .
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2 Answers
1for ellipse
SP=ePM
SP^{2}=e^{2}PM^{2}
comparing, focus ≡(1,2)
and equation of directrix = (3x+4y-5)
and e=1/3
now distance of centre from focus is =ae
and distance of centre from directrix is =a/e
there fore distance between focus and directrix is =ae-a/e=distance of(1,2) from directrix
now u have eccentricity an calculate a and then b using b^{2}=a^{2}(1-e^{2})