is a>b ???
Let P be a point on the ellipse \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 ,in the first or second quadrants,if the foci are S1 and S2,what is the minimum circum radius of \Delta PS_{1}S_{2}?
A) ae
B) be
C) ae/b
D) ae2/b
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4 Answers
tapanmast Vora
·2009-03-16 20:12:41
Dimag lagao!!
The 3rd pt. shud b on Y-axis naa....... thn only R will be min.
Vivek
·2009-03-17 18:59:53
no it is (A),if the 3rd pt is on y axis,i don't think it will be min radius(for this case r = a2/2b),i tried that before posting here.