The point (–4, 5) is the vertex of a square and one of its diagonals is 7x – y + 8 = 0. The equation of the other diagonal is
(A) 7x – y + 23 = 0 (B) 7y + x = 30 (C) 7y + x = 31 (D) x – 7y = 30
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1 Answers
rocky
·2010-05-25 05:13:59
the other diagonal is let x+7y+k=0 whare k is a constant..as the diagonals are perpendicular in a square
as The point (–4, 5) is the vertex of a square and as it doesnot satisfy 7x – y + 8 = 0.
so it must pass through x+7y+k=0
thus k=-31
hence The equation of the other diagonal is (C) 7y + x = 31