1i dont think we can calculate a until some other info is given
we only get
(b-a)/√2=c
the circles (x-a)^2 +(y-b)^2 =c^2 and (x-b)^2 +(y-a)^2 =c^2 touch each other....then a=____
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8 Answers
11i did
(a,b) is the mirror image of (b,a) (in y=x)
hence c is just the distance of (a,b) from y=x
62yeah i agree..
but i did not understnad why u wrote this i dont think we can calculate a until some other info is given
1i also don't think we can calculate a till something else is given
24question is complete..................dont think ,just answer.............
62yes satan,
ur answer is correct.. i dont know eureka why u think this is not the solution...
(b-a)/√2=c
basically one small mistake in rohan's solution was
|b-a|/√2=|c|
so u have to take 2 cases, a>b and b>a
if b>a, a=b-√2|c|
if a>b, a=b+√2|c|