39
Dr.House
·2009-03-23 11:28:48
well cant we take the circles to be all lying inside the big circle along the circumference ?
1
The Scorpion
·2009-03-23 11:31:42
yeah, dats what d question means...
give some initial steps plz or atleast a diagram...!!!
1
°ღ•๓ÑÏ…Î
·2009-03-23 11:32:37
aagaya :)
c d cenral angle for each equlatral tringle formed is 2pi/n for n sides polygon nw here u hav 24 sides
so itz 2pi/24
nw
(consider one of those trngles )
drwn a perpendicular frm d center to d side join d two centres
nw sin(pi/24) =2/hypo
d radius of bigger required circle is hypo+2
so itz
2cosec(pi/24)+2
39
Dr.House
·2009-03-23 11:43:14
the author of the question himself has said answers are A and D.
1
skygirl
·2009-03-23 11:44:50
arey nahi mereko neend ayi/aya hai ......... [dunno hindi grammar :P]
1
The Scorpion
·2009-03-23 11:47:57
thanx for d solution Ms. X (whats in name :P)... :D
well, derive option D from A... for one more pink post... ;) :P ..... (kiddin, i'll do it myself)...
thanx... :)