hyperbola

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from the point p[1,âˆš3] on the circle x²+y²=4 a tangent is drawn to the hyperbola x²/4-y²/1=1which meets its transverse axis at q.from q a line is drawn parallel to congugate axis ,which cuts the hyperbola at r above the x- axis ,then pr=

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Â°áƒ¦â€¢à¹“ÑÏ…Î ·2008-11-20 01:49:46

u noe d point on d circle u can find d equation of d tangent nw d tangent cuts d xaxis (transverse axis) u can find it by susbtitutin y=0 ind tangent equation
nw a line parallel to conjugate ie y axis it will hav x cordinate same ie u get 4 and y cordinate as r bt this point (4,r) lies on d hyeprbola so u get r and then use disytnce formula

cheero~

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Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

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+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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hyperbola

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