Find the equation and length of common tangents to x^2/a^2 - y^2/b^2=1 and y^2/a^2 -x^2/b^2=1 .
Please explain how you have solved it
Answers: x±y=±√(a^2-b^2)
And
√2(a^2+b^2)/√(a^2-b^2)
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Find the equation and length of common tangents to x^2/a^2 - y^2/b^2=1 and y^2/a^2 -x^2/b^2=1 .
Please explain how you have solved it
Answers: x±y=±√(a^2-b^2)
And
√2(a^2+b^2)/√(a^2-b^2)