More circle

C1 andC2 aretwo concentric circles the radius of C2 being twice of C1 from a point P on C2, tangents PA andPB are drawn to C1. Prove that the centroid of the triangle PAB lies on C1

9 Answers

24
eureka123 ·

this much is clear......what next???????

1
skygirl ·

Y COS2θ ?? does the angle change ? its the adius that changes ..

24
eureka123 ·

i think P point isnt fixed so θ should vary..............[12]


i maybe wrong

1
skygirl ·

without loss of generality,

center i am taking as (0,0)

let P (x1,y1) be a point on the big circle. so, x12+y12=4r2

chord of contact on smaller circle : x.x1+y.y1=r2

omy god! power cut.. ! shit shit.

1
skygirl ·

yes u are right.. but y 2 theta....

24
eureka123 ·

oh thats a typing mistake.......i was writing 2r and then wrote 2θ......sorry

1
Optimus Prime ·

let OP be x axis therefore P is (2r,0) and the equation of inner circle is x2+y2=r2

in triangle OAP, OA/OP=cos\Theta =r/2r=1/2

\Theta=60 , coordiantes of A are (rcos\Theta,rsin\Theta)=(r/2,r√3/2)

by symmetry co-ordinates of B are(r/2, -r√3/2)

G=[(2r+r/2+r/2)/3 , (0+r√3/2-r√3/2)/3]
=(r,0)

and this clearly lies on the inner circle

1
Optimus Prime ·

is my proof corrcet

62
Lokesh Verma ·

I think it wud be slightly better if you could refine the proof!

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