Find the Orthocentre of the triangle ABC where A=(a cos x1,a sin x1) B=(a cos x2,a sin x2) C=(a cos x3,a sin x3)
1see these points are the vertices of the triangle inscribed in a circle x2+y2=a2
now its circumcentre is (0,0) and the centroid u know .
centroid divides circumcentre and orthocenter in ratio 1:2.
u can now get the answer easily by using section formula
19use the formula for orthocentre of a triangle:
H----> Orthocentre
x coordinate of H= (x1tan A + x2tan B + x3tan C)/tan A + tan B + tan C
y coordinate of H = (y1tan A+ y2tan B + y3tan C )/tan A+tan B+tan C
Where , A(x1,y1) , B(x2,y2) , C(x3,y3) are the vertices of the triangle !!
1Thanks decoder...Organic i dont think we can solve it like u said..
