Plz say me how did u get
6y2-xy-x2=(3y+x)(2y-x)
....the rest i can solve
The following eqn represents two straight lines.
6y2-xy-x2+30y+36=0
Find their point of intersection and the angle between them.
for finding the slope you simply have to find the slope of the lines
6y2-xy-x2 = 0
you get (3y+x)(2y-x)
so we get the above eqtn is of the form
(3y+x+a)(2y-x+b)
now compare coefficients....
Can you complete therest?
Plz say me how did u get
6y2-xy-x2=(3y+x)(2y-x)
....the rest i can solve
factorize..
or solve for y in terms of x
the above expression is a quadratic in both x and y
so you can solve either for x or for y