11sorry two similar threads has been made...
please refer to
http://targetiit.com/iit-jee-forum/posts/parabola-from-ari-han-t-18365.html
1)The triangle formed by the tangent to the curve f(x) = x2 + bx - b at the point (1,1) and the co-ordinate axes lie in the first quadrant. If it's area is 2 then the value of b is:
a)-1 b)3 c)-3 d)1
ans c
2)If the normals from any point to the parabola x2 = 4y cuts the line y = 2 in points whose abscissae are in AP , then the slopes of the tangents at the three co-normal points are in:
a) AP b)GP c) HP d) None of these
ans b
3)A line L passing through the focus of the parabola y2 = 4(x-1) intersects the parabola in two distinct points. If 'm' be the slope of the line L then:
a) m E (-1,1) b) m E (-∞,-1) U (1 , ∞) c) m E R d) None of these
ans d
4)The latus rectum of the parabola x = at2 + bt + c and y = a't2 + b't + c' is
a)(aa' - bb')2(a2 + a'2)3/2 b)(ab' - a'b)2(a2 + a'2)3/2 c) (bb' - aa')2(b2 + b'2)3/2 d)(a'b - ab')2(b2 + b'2)3/2
ans b
5)answer not matching
If the tangents to to the parabola y2 = 4ax at the points (x1 , y1) and (x2 , y2) meet at (x3 , y3) then:
a)y3 = √y1y2 b) 2y3 = y1 + y2 c)2y3 = 1y1 + 1y2 d) None of these.
book answer a my answer b
1 to 4 are doubts (please give the solutions) and 5 I am not getting the answer as given by the book..(someone please confirm which is the correct answer)
-
UP 0 DOWN 0 0 6
6 Answers
11
212)
the equation of a normal to the parabola x^= 4y is m2y=m3x + 2m2+1
(easy to derive)
so from a point h,k three normals can be drawn say with slope m1,m2,m3
so we have m1*m2*m3=-1
and m1*m2 + m2*m3 + m1*m3 = 0
(theory of equation)
or 1/m1 + 1/m2 + 1/m3=0
the x co ordinates can be easily found
as they are in A.P we have
1/m13 + 1/m33 = 2/ m23
using a3 + b3 = (a+b)3 - 3ab(a+b)
u will get 1/m1 * 1/m3 = -(1/m2)
so done...
1(1)The given curve is as follows:
F(x)=x2+bx-b
y=x2+bx-b
Differentiating both sides w.r.t. to x.
dydx=2x+b
dydx(1,1)=2+b
The equation of line passing through (1,1) with slope 2+b
y-1=(2+b)(x-1)
y-1=(2+b)x-2-b
(2+b)x-y=1+b
x1+b2+b +y-(1+b)=1
So the coordinates of the triangle are
(0,0),((2+b)1+b,0),(0,-(1+b))
Use triangle formula to find the area.Pluggin these values.You will get b=-3.So (c) is the correct choice.
13) any line passing through focus intersects the parabola in 2 distinct points except the axis of parabola so their will be infinite lines passing through focus and cutting parabola in two points so slope(m)=real no except 0 becoz slope 0 means x axis which cannot be included.