1for other prob of std parabola...
1) find the normal eqn ....
2) put perpendicular to axis =0 .
The set of points on the asix of the parabola 2((x-1)2+(y-1)2)=(x+y)2. , from which 3 distinct normals can be drawn to the parabola , is the set of points (h,k) lying on the axis of the parabola such that
a) h>3
b) h>3/2
c) k>3/2
d) k>3
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4 Answers
11arey bhai i was keen to help u
but the shifting of axis of parabola is not in the syllabus of JEE 2009
1
62Hint: Partial solution
this equation above is same as
(x-y)2 -4(x+y) +4 =0
so you can take the new coordinate system as
X= x-y
Y= x+y-1
Now can you solve it?
