line joining S and t1 is perp. to line joining t2 and t3
thus 2t1t12-1. 2t2+t3 = -1
or 4t1t12-1 -t1 = -(t1 +t2 +t3 ) = k (say)
similarly for t2 and t3 .
4tt2-1 -t = k
whose roots are t1 ,t2,t3 .
on simplifying ,
f(t) = t3 +kt2 -5t -k =0
thus (t1-1)(t2-1)(t3-1) = f(1) = 1 +k -5 -k = -4