1how can we say with surety that dy/dx can have only 1/0/-1 values for this parabola ? please clarify
If the equation y=1+x-2√x represents a parabola then coordinates of vertex are?
Please explain how you solved it!
Answer is (1/4,1/4)
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8 Answers
1itzz nt a proper method bt a suitable shortcut
at the vertex of a parabola dy/dx = 1/0/-1
calculate dy/dx and put the three values n u'll get x=1/4
11HINT:just square and try getting rid of irrational terms.
then solve for general equation of a parabola.
AXIS2=LATUS RECTUM*(DIRECTRIX)
then use the facts that the eq of axis and eq of directrix needs to be perpendicular.
solve for the two eqs to get the vertex
262it should be tangent at vertex instead of directrix .
else you can use rotation of axis to get rid of xy term and then solve.
1not for all parabolas
bt here solving for directrix we get the condition and ultimately dy/dx=1/-1
9y-1-x=-2√x
Squaring both sides
y2+x2+1+2x-2y-2xy=4x
(x-y)2=2(x+y-12)
axis of parabola x-y=0
directrix x+y-12=0
solve you will get(14,14)