mid point --> [a(1+t2 ) /2 , at]
Substituting the mid point in that we get
(at)2 = 2a [a(1+t2 ) /2 - a/2 ]
Y2 = 4A[X - c]
A = a/2
X-c = x - a/2
Is the directrix ---> X + a/2 = 0 => x - a/2 + a/2 = 0
x = 0
The locus of the mid-point of the line segment joining the focus to a moving point on the parabola y2 = 4ax is another parabola with directrix : ?
[Show your working...I've found the midpoint of the segment in terms of parameter t but I'm not able to advance beyond that..]
mid point --> [a(1+t2 ) /2 , at]
Substituting the mid point in that we get
(at)2 = 2a [a(1+t2 ) /2 - a/2 ]
Y2 = 4A[X - c]
A = a/2
X-c = x - a/2
Is the directrix ---> X + a/2 = 0 => x - a/2 + a/2 = 0
x = 0
Uttara..what exactly have you done here?
Yes thats the ans..