11thanks Ajoy.
1)Find the equation to the straight line which passes through the given point (x',y') and is such that the given point bisects the part intercepted between the axes.
2) Find the eauation to the straight line which passes through the point (-4,3) & is such that the potion between the axes is is divided by the point in the ratio 5:3.
3)Find the equation to the straight lines which go through the origin and trisect the portion of the straight line 3x+y=12 which is intercepted between the axes of coordinates.
Don't give the solution, just give some hint & draw the figure so that I can see where I am failing in my visualization.
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5 Answers
12.take the points as A(a,0),B(0,b)....
Point p (-4,3) satisfies x/a+y/b=1..so you get one equation...
Again by section formula -4=(5*0+4b)(5+3)
...another equation
solve find a & b.,get equation.
13.*Find the intercepts of line A(a,0),B(0,b)
*find points of trisection using section formula
*the points satisfies y=mx
*you get m,hence you can find the equations.
