@decoder
inradius is not the distance from the centre of the incircle to any of the vertices....
it is the perpendicular distance of the incentre from any of the sides........
In ΔABC A=(1,2).
Internal angle bisectors through B and C are y=x and y=-2x. Inradius of ΔABC is:
A) 1√3
B) 1√2
C) 23
D) None of these
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8 Answers
Arshad ~Died~
·2009-09-18 08:04:16
decoder
·2009-09-19 01:31:53
sorry........sorry.......... i have made a blunder in hurry......sorry again
Bicchuram Aveek
·2009-09-19 13:24:30
To all who have viewed this question....i've solved it but it's a bit lengthy..........actually it is given in FIITJEE RSM but the solution there is wrong.