simply use family of circles ;
u will get P≠-1 and P≠√6
i think if these circles touch or cut one another then the other condition is satisfied..they shud nt touch at (1,1) but one of the points if they cut may be (1,1)
i think this kills the problem!
sir, in series, p-series problems if n is not multiplay with 2 . then how we solve this ?
i'm getting all values of p
@shubhodip
i too used family, n got k=[p2-6]/2p+7
here k=0 or 1/0 is okay, isn't it?
@subhodip
answers given by various institutes differ on this problem some say
(1) and some others say (2)
i solved and got (2)....i want you guys to come out with wat's right!