Consider an equilateral triangle ABC with side length 2.1cm. Find the minimum number of equilateral triangles with side length 1cm which can be placed over ΔABC so that it is completely covered.
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1 Answers
69Number of triangles that can be placed along one side = 21
Therefore, total number of triangles
= sum of the first 21 odd numbers = 1+3+5+7+9+11+13+15+17+19+21+23+25+27+29+31+33+35+37+39+ 41 = 212 =441
Soumyadeep Basu Side length is 2.1cm, not 21cm.Upvote·0· Reply ·2014-05-06 00:40:09
Sourish Ghosh @soumyadeep http://www.amt.edu.au/wfnmc/mc20101.pdf- Soumyadeep Basu Thanks a lot, Sourish.