Vectors

|a|=2,a.b =1,angle between a and b = 60 . r is any vector satisfying:

r.a=2
r.b=8

(r+2a-10b).(a x b) = 4√3
(r+2a-10b) = λ(a x b)

then λ =

A)1/2
B)2
C)1/4
D)4

6 Answers

1
Vivek ·

anyone?

33
Abhishek Priyam ·

|a||b|cos(600)=1
|b|=1

Let r=la+mb+naxb

(la+mb+naxb).a=2
l|a|2+ma.b=2
4l+m=2

also r.b=8
(la+mb+naxb).b=8
la.b+m|b|2=8
l+m=8

solve for l and m
l=-2 m=10

also
(r+2a-10b).(a x b) = 4√3
(-2a+10b+naxb+2a-10b).(axb) = 4√3 ..putting value of l and m

n|(axb)|2=4√3
n(√3)2=4√3
n=4√3/3

λ=4√3/3

none matching... may be some calculation mistake

33
Abhishek Priyam ·

but i can find no mistake in this.. may be options wrong... :O

1
Vivek ·

i got the same answer you got,thats why i posted here

33
Abhishek Priyam ·

options are wrong then.. :)

1
Vivek ·

possible,very much possible coz the src is fiitjee

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