Recently Active Disucss Test Question Questions

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A satellite of mass m is orbiting the earth at a height h from its surface.(mass of earth is M and its radius is R) (55) Kinetic energy of the satellite (a) -GMm/(R+h) (56) Potential energy of the satellite (b) GMm/2(R+h) (57 ...

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mathc the following: For motion in a straight line (51) Acceleration (a) is always along the motion of particle (52) Speed (b) maybe along the motion of the particle (53) Velocity (c) is always opposite to motion of particle ...

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Match (89) N2(g)+O2(g) [eq] 2NO(g) (a) Unaffected by inert gas addition (90) A(s)[eq]B(s)+C(g) (b) Forward shift by rise in pressure (91) N2(g)+3H2(g) [eq] 2NH3(g) (c) Unaffected by increase in pressure (92) PCl5(g)[eq] PCl3( ...

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Match (85) ClF3 (a) Trigonal Planar (86) PF3 (b) T-shaped (87) BF3 (c) Pyramidal (88) SF6 (d) Octahedral ...

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primary alcohol formed is ...

E on iodoform reaction gives ...

comprehension for ques 75-77 A(C6H12) HCl >B+C (both are C6H13Cl) B alc. KOH >D(isomer of A) D ozonolysisl >E (negative test with Fehling solution but respoonds to iodoform test) A ozonolysis >F+G(both give positi ...

STATEMENT-I: Acetic acid does not undergo haloform reaction. STATEMENT-II: Acetic acid has no alpha hydrogens. ...

STATEMENT-I: In strongly acidic solutions, aniline becomes more reactive towards elctrophilic reagents. STATEMENT-II: The amino group being completely protonated in strongly acidic solution, the lone pair of electrons on the ...

STATEMENT-I: 1-butene on reaction with HBr in the presence of a peroxide produces 1-bromobutane. STATEMENT-II: It involves the formation of a primary radical. ...

The distance of the line L from the plane containing the incidence and the reflected rays is ...

The image of point A is ...

comprehension for ques 14-16 A line passing through A(2,2,4) and parallel to line L ≡(x-2)=(y-1)=(z-2)/3 is incident of the mirror plane x+2y+2z-5=0. The equation of the reflected ray is ...

Statement 1) Area of the points formed by Z1, Z2, Z1/2+Z2/2 is zero Statement 2) Arg(Z1-Z2) = Arg (Z1- (Z1+Z2)/2) ...

Statement 1 : 1r + 2r + 3r ..... + nr > n. (n!)r/n Statement 2 : AM GM Inequality! ...

Statement 1: The points 2+4i, 2-4i, 3+3i and 3-3i are of a cyclic quadrilateral Statement 2: The points are concyclic if Arg(Z1-Z3)/(Z2-Z3) = Arg(Z1-Z4)/(Z2-Z4) ...