Recently Active Disucss Test Question Questions

find the domain of &radic(sinx+cosx) + &radic(-sinx+cosx) ...

√(1-x2) + √(x2 + 4x + 5) + √(x2+π) ...

√{(|x|-x)/(|x|+x)} + {(|x|-x)/(|x|+x)}2 ...

find the domain of ln{|x|-x} ...

find the domain of x2/x ...

find the domain of tanx*cosx ...

find the domain of √{|√x2+x3+1/x3|} ...

find the domain of (x2+2x+3)/(x2+1) - (x2+2x+37sinx)/{sin2x + tan2x + cos2x)} ...

1+3+5+..+99 ...

A man has 390000 rupees on retirement. He gets 5000 per month as pension. his expenditure of 1st month is 5000. His expenditure increases by Rs 500 every month. When will he be bankrupt? ...

if the sum of p terms equals the sum of q terms which is equal to a, sum of p+q terms = ...

sum of n terms is 5n2-3n. pth term is given by? ...

pth term of an AP is q, qth term is p. what is the p+qth term ? ...

find the sum of the 1st 10 terms of the series whose first 3 terms are (2a2-1)/a, a, 1/a ...

10th term of a series,if the sum of 1st n terms is 10n2+20n ...

10th term of a series whose sum of 1st n terms is n2+2n ...

7th term of a series, if the sum of 1st n terms if given by 4n ...

15th terms of the series whose nth term is 4n+1 ...

A point object is at the origin. A plane mirror is placed parallel to the YZ plane at X=4. Find the coordinate of the image. ...

Find the number of images formed by two plane mirrors placed along the same plane. at a distance of 5 m from an object. The mirrors are at a distance of 1 m from each other. Both mirrors are squares of side 1 m. ...

If the angle between two mirrors is increased by 15 degrees, the no of images decreases by 4. What is the initial angle between them? ...

Find the number of images formed by two mirrors at an angle of 60 degree ...

There is a mirror 1 metre wide parallel to a wall. The mirror is 19.5 metres from one end of the wall. Tom sits at that end. What distance along the wall will Jerry be able to see Tom ...

If a plane mirror is rotated by an angle θ, the reflected ray is rotated by ...

<table> <tr><td>π/2</td></tr> <tr><td>&integ;(sinx/cosx)dx =</td></tr> <tr><td>π/4</td></tr> </table> ...

<table> <tr><td>∞</td></tr> <tr><td>&integ;x/(1+x4)dx =</td></tr> <tr><td>0</td></tr> </table> ...

<table> <tr><td>π</td></tr> <tr><td>&integ;(sinx+1)(cosx+1)dx =</td></tr> <tr><td>-π</td></tr> </table> ...

<table> <tr><td>π/2</td></tr> <tr><td>&integ;(xtan|x|(x2-1)ln|x|)dx =</td></tr> <tr><td>-π/2</td></tr> </table> ...

<table> <tr><td>2</td></tr> <tr><td>&integ;(x+1)(x-1)dx =</td></tr> <tr><td>0</td></tr> </table> ...

<table> <tr><td>1</td></tr> <tr><td>&integ;(x(x+1)2(x-1)2)dx =</td></tr> <tr><td>-1</td></tr> </table> ...