npt2 m45

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Let Aâ‰¡(9,6), B(4,-4) be two points on parabola Y²=4x and P(t²,2t), tÎµ[-2,3] be a variable point on it such that area of Î”PAB is maximum, then point P will be

A) (4,4) B) (3,-2âˆš3) C) (4,1) D) (1/4,1)

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Avinav Prakash ·2010-03-01 07:33:58

ans is .d

use determinant to find the area of traiangle in terms of t

then use derivatives......

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UTTARA ·2010-03-01 07:40:02

U're ans is correct

I got the prob

But wanted to confirm the ans so i posted

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Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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npt2 m45

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