QT P2 C 8

In the freezing point depression experiment, it is observed that

(a) the decrease in freezing point of CH3COOH(Y) is lower than that of 0. 1 M of CH3COOH(Y) in water.

(b)the decrease in freezing point in the two solutions is same.

(c)at the freezing point the solvent begins to freeze.

(d)relative lowering of vapour pressure of solution (X) is more than (Y).

6 Answers

1
Tapas Gandhi ·

Question seems incomplete???

C) is correct

4
UTTARA ·

ans is a & c

1357
Manish Shankar ·

Something is missing in option (A)

4
UTTARA ·

this is a qs from BT FST2

In (A) cant it be this way ??

The decrease in freezing point of CH3COOH(Y)--->pure

is lower than that of 0. 1 M of CH3COOH(Y) in water.-----> In solution

29
govind ·

Ya UTTARA u r ryt abt the A option
When CH3COOH is in pure form then it exists as a dimer so van't hoff factor i = 0.5
when CH3COOH is dissolved in water it partially dissociates into CH3COO- and H+ so i > 1
decrease in freezing point α i
so in the first case decrease in freezing point is less than the second..

4
UTTARA ·

Thanks Govind

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