1 Answers
Asish Mahapatra
·2009-10-25 09:04:55
x+y/2 + y/2 + z/3 + z/3 + z/36 ≥ (xy2z32233)1/6 (AM - GM)
So, xy2z3 ≤ 2233
x+y/2 + y/2 + z/3 + z/3 + z/36 ≥ (xy2z32233)1/6 (AM - GM)
So, xy2z3 ≤ 2233