Test:102 QNo:3

find the tangent of angle between two diameters of ellipse x2/4+y2/3=1 through P(π/6) and Q(2π/3)

2 Answers

1
Avinav Prakash ·

TEH GIVEN DIAMETERS ARE CONJUAGTE....
PARAMETRICALY....TTHE PTS ..(3cosθ,√2sinθ)...

as the diametrs pass thru origin.....m1=0.5 .....m2=-1.5

so tanθ=8

1
Avinav Prakash ·

TEH GIVEN DIAMETERS ARE CONJUAGTE....
PARAMETRICALY....TTHE PTS ..(3cosθ,√2sinθ)...

as the diametrs pass thru origin.....m1=0.5 .....m2=-1.5

so tanθ=8

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