TEH GIVEN DIAMETERS ARE CONJUAGTE....
PARAMETRICALY....TTHE PTS ..(3cosθ,√2sinθ)...
as the diametrs pass thru origin.....m1=0.5 .....m2=-1.5
so tanθ=8
find the tangent of angle between two diameters of ellipse x2/4+y2/3=1 through P(π/6) and Q(2π/3)
TEH GIVEN DIAMETERS ARE CONJUAGTE....
PARAMETRICALY....TTHE PTS ..(3cosθ,√2sinθ)...
as the diametrs pass thru origin.....m1=0.5 .....m2=-1.5
so tanθ=8
TEH GIVEN DIAMETERS ARE CONJUAGTE....
PARAMETRICALY....TTHE PTS ..(3cosθ,√2sinθ)...
as the diametrs pass thru origin.....m1=0.5 .....m2=-1.5
so tanθ=8