Test:14 QNo:3

find the no. of ways to seat them in straight chairs such that no girl sits together.

3 Answers

if 4 boys and 3 girls are arranged then the total no. of permutations will be 7!

if 3 girls are to sit together then permutations are 5!*3!

so no. of ways in which no girls sits together is 7! - 5!*3! = 4320

no suprad
in your answer 3 girls r not together
but 2 can be together in your answer

i think the answer must be 5*4!*3! as 5 case will be there

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