The rate constant of a reaction at temperature 200K is 10 times less than the rate constant at 400K, find the activation energy of the reaction
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1 Answers
Avik
·2010-03-12 13:43:26
Isn't this giving it out....
ln(K2/K1) = Ea/R*(1/T1- 1/T2) ...?
Waise, i do not know whose doubt it is.