please explain.....
The reduction potential of two half cell reactions are
PbSO4+2e-→Pb+SO42- E°=-0.27V
Ag+(aq)+e-→Ag(s) E°=0.75V
The feasible reaction will be
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2 Answers
Vivek @ Born this Way
·2012-04-02 04:59:33
Calculate ΔG° for the cells. Those with negative value are spontanoeus.