which is harder to break \sigma or \pi
it is pi bond which is p-p overlap
hence p-p overlap is WEAKER than s-s
u compared all as sigma bonds it is not mentioned in Q to assume so
taking p-p bond as pi bonds gives b as the correct one
The strength of bonds formed by 2s-2s, 2p-2p and 2p-2s overlap has the order
Q4 The strength of bonds formed by 2s-2s, 2p-2p and 2p-2s overlap has the order
a) s-s<s-p<p-p
b) s-s>s-p>p-p
c) s-p<s-s<p-p
d) p-p<s-s<s-p
Your Answer: (a)
Correct Answer: (b)
Score: -1
Explaination :
s-s strength is highest & p-p has lowest
nature of sigma bond bond strength
s-s 1.0
s-p 1.73
p-p 3.0
(reference: http://www.citycollegiate.com/bond_theoryXIa.htm)
(The relative strength of a sigma bond is related to the extent of overlap of the atomic orbitals. This is known as the 'principle of maximum overlap'.
Due to spherical charge distribution in s-orbital, generally s-s overlapping is not so effective as s-p and p-p overlapping.
Where p-orbitals have directional charge distribution and longer lobes which cause more effective overlapping. Thus s-s sigma bond is relatively weak.)
which is harder to break \sigma or \pi
it is pi bond which is p-p overlap
hence p-p overlap is WEAKER than s-s
u compared all as sigma bonds it is not mentioned in Q to assume so
taking p-p bond as pi bonds gives b as the correct one