The soln given for this question is absolutely wrong.
soln is x ε [1,√2).
hence answer shud b none of these option d.
Solve:
[x2]-3[x]+2≤0, where [ ] is greatest integer fn.
1st of all x cannot be negative as all the terms become +ve.
Morover, x cannot be <1 (obvious, isn't it?)
So, x≥1
Now, The inequality x2-x+2≤0 is satisfied for 1≤x≤2
So, the given inequality will be satisfied for a subset of [1,2]
It is apparent that for x≥√2 the given inequality is not satisfied.
So x ε [1,√2)
The soln given for this question is absolutely wrong.
soln is x ε [1,√2).
hence answer shud b none of these option d.
give me my 100 percent marks :(((((
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