Test:347 QNo:38

Comprehension for 38-40

Any body thrown at some angle on the earth surface follows a parabolic path.
The motion of the body is given as
y=xtanθ0-gx2/2(v0cosθ0)2
where θ0 is the angle of projection and v0 is the velocity of projection
coefficient of restitution is defined as the ratio of velocity of separation and velocity of approach.
Let there are two bodies 1 and 2. For 1 coefficient of restitution is 3/5 and for 2 it is 1
Both the bodies are projected as same angle and with same velocity. The bodies continue to move after rebounding.
velocity of of the bodies is given as v0=15i+20j m/s
take g=10 m/s2

Find the time after which body 1 will stop

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