Q44 a) -(log2)2/4
b) -(log2)2 c) -(log2)2/2 d) -(log2)2/8
6 Answers
°ღ•๓ÑÏ…Î
·2009-04-24 08:58:17
put losinx=t
so ur int bcums
t dt
so itz
t^2/2
so log sinx d whole squre /2
Mani Pal Singh
·2009-04-24 08:59:13
integrate it by parts
Take the 1st function as log sinx and 2nd function as cot x
USE
∫cotx=lnsinx
i hope u will get ur answer
if still doubt persists then ask again!!!!!!
Manish Shankar
·2009-04-24 09:23:53
(1/2)[(logsinx)2]pi/6pi/2=(1/2)[0-(log1/2)2]=-(log2)2/2
whats your doubt here