Oh.....ok...thanx vivek
3 Answers
Anirudh Narayanan
·2009-04-20 23:10:48
HOW, VIVEK?
\lim_{x\rightarrow 0}\frac{\sqrt{1-cos2\pi x}}{x}\; =\; \lim_{x\rightarrow 0}\frac{\sqrt{2sin^2\pi x}}{x}
=\; \lim_{x\rightarrow 0}\frac{\sqrt{2}sin\pi x}{\pi x}\; \pi = \sqrt{2}\pi ????