(2y3+x)dy=ydx
2y3 dy = ydx - xdy
2y dy = (ydx - xdy )/y2
2y dy = d(x/y)
∫2y dy = ∫d(x/y)
y2 = x/y + c
c = 1
y2 = x/y + 1
y3 = x + y
so correct answer is B not A
solve the differential equation (2y3+x)dy=ydx ,the curve passes through (0,1)
(2y3+x)dy=ydx
2y3 dy = ydx - xdy
2y dy = (ydx - xdy )/y2
2y dy = d(x/y)
∫2y dy = ∫d(x/y)
y2 = x/y + c
c = 1
y2 = x/y + 1
y3 = x + y
so correct answer is B not A