Test:351 QNo:51

solve the differential equation (2y3+x)dy=ydx ,the curve passes through (0,1)

3 Answers

1
ANKIT MAHATO ·

(2y3+x)dy=ydx
2y3 dy = ydx - xdy

2y dy = (ydx - xdy )/y2

2y dy = d(x/y)

∫2y dy = ∫d(x/y)

y2 = x/y + c

c = 1

y2 = x/y + 1

y3 = x + y

so correct answer is B not A

1357
Manish Shankar ·

yes the answer is B

1
ANKIT MAHATO ·

still showing -1 :o

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