A cart of mass M has a block of mass m in contact with it as shown in figure. The coefficient of friction between the block and the car is μ. What is the minimum acceleration of the car so that that the block m does not fall?
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2 Answers
1arey uspar pseudo force lagega
so
N=ma
frcition=mgfrcition=uN
so
uma=mg
so a=g/u
1let the normal force on the small mass m be N
let the friction be f
so as it is accelerating with the cart in forward dir.
we have N=ma
further for vrtical equillibrium we have
f=mg
but f<=μN=μma
so we have
μma>=mg
a>=g/μ