I'M GETTING sec2( log x )x. tan( log x ) and given is 2x*sin logx2
4 Answers
Manmay kumar Mohanty
·2010-03-04 20:46:21
Manish Shankar
·2010-06-30 07:16:08
sec2(logx)/xtan(logx)=1/x.sin(logx)cos(logx)=2/x.(2sinlogx.coslogx)=2/x.sin(2logx)=2/x.sinlogx2
it was easy :)