Qualitative :
as nothing is mentioned in Q , i suppose both emfs are clockwise
Now inc in i1 will induce backemf in ring one and forward emf for ring2
similar case for i2
Quantitative:
L1 ,L2 - self inductance
K1,K2 - mutual inductance ( i hope u arent asking derivation of exact formula , its tedious )
then for loop one by applying kirchoffs law
L1(di1/dt) - K2(di2/dt) + e1 -i1r1=0
for loop 2
L2(di2/dt) - K1(di1/dt) + e2 -i2r2=0
solving these i got something very interesting!!
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(L2L1 - K2K1)d2i1/dt - (L2r1 + L1r2 )di1/dt + i1(r1r2) = e1r2
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now the abv eq is solvable and has multiple solutions .
but one interesting solution that can be found by observing is i1 = e1/r1 (which is a constant and the other derivatives are 0 )
but nature doesnt permit that solution as for i to be established , it takes a small but definite time ( as speed of EM waves = c )
but after infinite time , i1 = e1/r1 obviously and similar for i2 .
can u solve the abv eq using mathematica and post it ith power ??