BET u cant solve it[two capacitors...]

a capacitor wid charge Q is attached tpo anoder capacitir of same capacitence C through a resistor of R.....find the charge on d oder capacitor as a fucntion of timee..:)

2 Answers

3
iitimcomin ·

-q/C + (Q-q)/C = Rdq/dt

(-2q+Q)/C = Rdq/dt

-t/RC = 1/2 ln(-2q+Q/(Q))

[(Q)-(Q)e-2t/RC]/2

1
RAY ·

iitimcomin u got it right dude....:)
shin chan cartoon nahi hai ye sums yaar...[:D]

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