-q/C + (Q-q)/C = Rdq/dt
(-2q+Q)/C = Rdq/dt
-t/RC = 1/2 ln(-2q+Q/(Q))
[(Q)-(Q)e-2t/RC]/2
a capacitor wid charge Q is attached tpo anoder capacitir of same capacitence C through a resistor of R.....find the charge on d oder capacitor as a fucntion of timee..:)
-q/C + (Q-q)/C = Rdq/dt
(-2q+Q)/C = Rdq/dt
-t/RC = 1/2 ln(-2q+Q/(Q))
[(Q)-(Q)e-2t/RC]/2
iitimcomin u got it right dude....:)
shin chan cartoon nahi hai ye sums yaar...[:D]