1
aieeee
·2009-09-08 21:49:37
If a charged capacitor is isolated from d battery and then the dielectric constant is inserted,then V = V0 / k
If d capacitor remains connected,when dielectric is being inserted , then V = V0.
actually,this phenomena depends on conservation of energy by the capacitors , when d dielectric is inserted and taken out.
4
UTTARA
·2009-09-09 01:14:28
The magnitude of electric field decreases when dielectric is placed but potential increases continuously across the plates
right !!!!
62
Lokesh Verma
·2009-09-09 01:18:26
Electic field decreases...
-E.ds' integral is the magnitude of the potential...
IF E decreases, then The magnitude of the potential will decrease..
but if you are talking about the "potential at a point" .. THen it will increase....
1
RAY
·2009-09-09 23:15:51
just add K to every \varepsilon\o
epselon naught i mean..n c whether it decreasesor increases.:)