30Another doubt that I had in this question was that would the electron-proton pair separate at all considering the fact that they were released as a pair. So the electrostatic forces of attraction would be very high isn't it?
Q. The plates of a capacitor are 2 cm apart. An electron-proton pair is released somwhere in the gap between the plates and it is found that the proton reaches the negative plate at the same time as the electron reaches the positive plate. At what distance from the negative plate was the pair released?
Attempt:
Assuming the required distance to be x and the net electric field to be E.
Magnitude of Charge on the proton and electron is e
x=Ee2mpt2
2-x = Ee2met2
2-xx=mpme
the answer coming is incorrect .. [2]
HCV Q 23.
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30
30Exactly.. Thats what I did. HCV says x = 1.08 x 10-8 cm.
And over here arent we getting 1.08 x 10-3 cm?
1HCV answer could be wrong. unless you are making a mistake in the units. :P
@ homagni, not the correct place to post this question.
numerator=sin2x+cos2x
divide numerator, denominator by cos4x, put tanx=t
divide numerator and denominator by t2, now write denominator as (t-1/t)2+2. the put t-1/t=p and your done.
this is a typical example of 'algebraic twins'
cheers!