oh no i hate this type of pbm.how will be the charge division.
how to apply gauss's law.neone pls explain this pbm .
each palte shown above has surface area A on one side and the separation between consequitive plates is d.the emf of the battery connected is 10 volts.find the magnitude of charge supplied by the battery tp each of the plates connected to it...
oh no i hate this type of pbm.how will be the charge division.
how to apply gauss's law.neone pls explain this pbm .
Here three capacitors r formed, each of area A.
Seperation b/w the plates = d
So, Capacitance C = e0 A /d
As three capacitors r arranged in series,
Therefore Ceq = C/3 = e0 A / 3d
So, the total charge to the capacitor = Ceq V = 10 e0 A / 3d
Eureka think once again
How V1 can be at positive as well as negative terminal of the battery?
what's the use of battery then