Capacitors

charge on B = 2 X 12 = 24 microfarad

since A and B are in series....eq capacitance = 4/3 microfarad

now u can find out how 24 microfarad will be distributed on the 2 capacitors

24/(4+2) = 4 microfarad......so

charge on B = 4 X 2 = 8 microfarad
charge on A = 4 X 4 = 16 microfarad

so wateva be the value of charge on 4 microfarad capacitor.....find out the heat in transfering that amount of charge ((CV^2)/2)

V = Q/C = 4

so answer according to me should be 32 J

is it correct??

thanks dude that was a doubt..