A conducting ring of radius L=2m is placed on x-y plane, having its centre at the origin. A uniform magnetic field 5T(-k) exists in the space. A conducting rod PQ of mass M & length 2L is placed along the diameter of the rail. Rod is free to rotate about z axis on the smothering. A resistance R is connected to the centre O & periphery of the ring. At t=0, PQ is given ang. velocity 1 (k) rad/sec.
Find the ratio of the numerical values of the charge flown through resistor to the heat generated through the resistor during the time interval the rod keeps on rotating.
ANS: 5
I m bit confused .....
REPLY SOON............!!!!!!!!!!!!
3howd did u get answer key for exam .... even i rote ftse!! but didnt get any soln. booklet!!!!
3dunno if rite
ans=∫i^2Rdt[0->∞]/∫idt[0->∞]...(1)
we have
iR = BL^2W/8 ... (2)
nd torque due to i thru the ...
T= ∫BiLdL [0 --> L/2] ...(3)
-dW/dt = T ...(4)
get i and w as a fxn of time ... we see the rod stops only at t = infinity ......
put i(t) in eqxn 1 .........
3nd how did u remember question exactly they took away the q papers na !!!
1dude it also came last year in thier AITS.........may be he had taken it from there
1tis was the best q
in the central rod two battries will be induced in opp directions wit emf e=1/4 L^2 W
then solve for current