E = 4/3 V
Current in,
R1 = 3.33 mA
R2 = 46.67 mA
- Akash Anand Excellent work.Upvote·0· Reply ·2013-07-05 05:02:49
- Anuradha Yadav can u plzzz show the swolution....i'm unable to solve it
- Anuradha Yadav i mean solution
E = 4/3 V
Current in,
R1 = 3.33 mA
R2 = 46.67 mA
let i current leave the cell E1.
let i1 = 50mA
Applying Kirchoff's Law,
100( i - i1 ) + 50i = 2
-100( i - i1 ) + 20i1 = E2