Current & Resistance

Ans 1 ..Break the contact of triangle at point C from the line AB and then u can easily solve it..

and in 2 how much current is coming from branch H

for 1 apply symmetry or connection removal..

Done...thnx to govind.

2) Current frm H --- x

2+x = 1 +3 (Junc.n law after V battery)
x=2 Amp

V_G-V_H = 2x4 -3 + 2x2 -2x1 = 7V

Thnx to sandipan also :)