1ok.
This is my doubt....framed this question myself
will the battery supply charge in the circuit or will it be dead?????
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22 Answers
3Take a pen torch cell and then connect with ends with copper wire after a long time the copper wire will burns.This will happens in this case also.
24@philip..
whatever I wrote in post#20 has been approved by Kaymant Sir.. [1]
1if we take wires ideal then the situation is contradictory
as we would have 2 different potentials at the same point
practically if the wire is of very low resistance then the wire heats up and melts (unless heating raises its resistance to a suitable level ??)
all this while there is definitely current (albeit negligible) in the other wire
and by then if the battery is not damaged the current should flow in both the loops afterwards
24Okk..so final ans is
a) If we take wires to be ideal...then current flows through conducting wire only.....
b)if we dont take it ideal...then initially current is through conducting wire..and after some time it melts away..so that ..current is in bot hthe loops
24so no current in top loop and current of 10A in lower loop?
and will the current pass through conducting wire or through resistance??
or both ?
66So what? There is an electric field inside the wire which is created by the battery. That will make the current flow. I understand that you are under the impression that the wire is at the same potential throughout. But that is not correct. It is the purpose of the battery to create a constant potential difference between its terminals.
66Ideally speaking the diagrams in #4 are not equivalent. For the original problem, the battery of course works. However, there is no current in the upper loop containing the two resistances. But there is a current in the lower loop formed by the battery and the wire circumventing the lonely resistance. This current is limited by the internal resistance of the battery itself.
1all current travels through the wire with parell(r=0), it will get short circuited
3the wire will melt away and therefore the final circuit will be two resistors , a battery which are connected in series.
33ghar me circuit jod kar dekh lo.. :P
lekin pahle tumko resistance less wire dhundna padega.. :D
24so what actually will happen to battery....................will it work or not????
62practically what will happen is that
V2/R will become very very very large in the wire with "No" resistance
so that will melt away.
but theoretically this is not possible...
24my first choice too was short circuit but then another thought coming to my mind is that ::
am i correct????
