24its not that much easy also..........
14 Answers
1no . that's not right.
only the Resistances with 2 ohms are removable. so effective R = 7/3 ohms.
11Circuit is symmetrical about the two 2 Ω resistances........ So same amount of current will enter both branches.......so 2 ohm resistors can be neglected. this gives us an equvalent resistance of 7/3 ohms.
P.S:
IT IS MY REQUEST THAT THIS POST NOT BE PINKED
1nah sry guys . It was bakwaas , so edited. wheatstone method suffices. not symmetry.the ckt is not symmetrical abt BED.
1isn't the circuit symmetrical about the other side also?.............
24but we need to calculate eq resistance b/w A and B .........so we have to find symmetry about a line which is perpendicular bisector to imaginary line joining AB